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#11




Quote:
My guess is that the fastest time you see is actually the fastest, but the slowest is at the 90 percentile mark, or something like this. If it really showed the slowest, then you would see times above 10,000 seconds (3 hours) all the time, since you can come back to a puzzle up to 24 hours later. I've played logicpuzzles.org for a while, and theorized that the slowest times don't show up there, using the same reasoning. I'm glad you actually are recording this data, as it validates my theory! 
#12




When I do these puzzles now, I just record my time, the fastest time, and the median time. So, I write something like this:
Code:
180, f=80, median=360 If you play a lot of puzzles, you'll see values that are not whole numbers some times. These can only appear in the 2nd or 4th spot of the graph. The number in the second spot of the graph will be xxxx.5 if fastest time + the median time is an odd number. The 4th spot of the graph is almost always an integer, but can be xxxx.5 if the median + your time is an odd number and your time is larger than the median time multiplied by 5. Every size of puzzle has a maximum and minimum amount of points that you can score. I haven't experimented much to figure out the minimums, but the maximums are: Code:
8 points for a 5x5 26 points for a 7x7 56 points for a 9x9 116 points for an 11x11 161 points for an 11x15 199 points for an 11x19 Code:
Your percentile = 1.00 if your time is better than the fastest time. Your percentile = 0.50 if your time is the same as the median. Your percentile = 0.00 if your time is worse than the median * 5 Your percentile = 1  1/2 * (t  f) / (m  f) If your time (t) is between the median time (m) and point 5 on the graph (m*5), then your percentile is approximately: Your percentile = 1/2  (((t  m) / m)  1) / 8 I've noticed my calculations are a little off for the scenarios where I'm between (m) and (m*5), so the formula I listed above for your percentile in those cases may be off. Now that you know your percentile, you can multiply it times the max points available for the puzzle. As long as this value is larger than the minimum number of points for the puzzle, this is what you will get. If it is lower than the minimum value for the puzzle, then you get the minimum value. So, back to our example, where I recorded the following for an 11x11: Code:
180, f=80, median=360 That comes out to be 1  0.5 * (100 / 480) = 0.8214 Now you multiply that by the maximum points for a puzzle of that size (116): 116 * 0.8214 = 95.29 Now you round that to the nearest integer (95), and that is the number of points you get! Last edited by uigrad; 01122017 at 01:54 PM. Reason: Small correction 
#13




Quote:
I took the slowest times you listed (2230 and 2170), and divided them by 5 to get the medians: 446 and 434. Then I used your times (256 and 149) along with the fastest times (133 and 133) and the medians (446 and 434) to get your percentiles: (.8035 and .9734) From there, I use the max value for an 11x11 (116) and get your scores (93.21 and 112.92). You recorded 93 and 113, which is exactly what I get after rounding. Quote:
Higher 'slow times' just indicate higher medians, and yes they do affect score. But your original post (several years ago now) prompted me to figure this out myself, so it was certainly not futile, haha! 
#14




the minimum for a 11×19 is 20

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