It's claiming that R2C2 can only be 7, since 1, 2, 4, 5, 6, 8, and 9 already exist in Row 2. BUT 3 DOESN'T. So someone smarter than me tell me why R2C2 HAS to be 7. Or am I blind as well as stupid?
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I don't know if this is how they're trying to explain it, but I see that R2C1, R2C2, and R9C2 are all either 3 or 7. This means that R9C1 can't be 3 or 7 because then the puzzle would be unsolvable. Therefore, R9C2 must be 3 (only 3 in box), so R2C2 has to be 7. -
I finally figured it out. It would have been much easier had I read the instructions fully. The last instruction states that a pair of boxes without an X or V symbol between them cannot add up to 5 or 10. since R3C2 is value 2, R2C2 cannot be value 3.
Many years ago, I was taught in a Navy school to "RTFQ" (read the freaking question). I guess in this case I should have "RTFI" (read the freaking instructions).Comment
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